If the <em>n</em>-th term of the sequence is given by <em>n</em> ² - 2, then the 5th term is obtained by simply replacing <em>n</em> with 5 :
5² - 2 = 25 - 2 = 23
Answer: 5.9 cm for both triangles.
Step-by-step explanation:
Hi, since the situation forms 2 right triangles we have to apply the Pythagorean Theorem:
c^2 = a^2 + b^2
Where c is the hypotenuse of a triangle (the longest side of the triangle) and a and b are the other sides.
Replacing with the values given:
c^2 = 3^2 + 5^2
c^2 = 9+25
c^2 = 34
c = √34
c = 5.9 cm
Since both triangles are identical ( same side lengths) the hypotenuse is the same for both, 5.9 cm.
Feel free to ask for more if needed or if you did not understand something.
1 Convert 12\frac{2}{3}12
3
2
to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a
c
b
=
c
ac+b
\frac{12\times 3+2}{3}\times 3\frac{1}{4}
3
12×3+2
×3
4
1
2 Simplify 12\times 312×3 to 3636
\frac{36+2}{3}\times 3\frac{1}{4}
3
36+2
×3
4
1
3 Simplify 36+236+2 to 3838
\frac{38}{3}\times 3\frac{1}{4}
3
38
×3
4
1
4 Convert 3\frac{1}{4}3
4
1
to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a
c
b
=
c
ac+b
\frac{38}{3}\times \frac{3\times 4+1}{4}
3
38
×
4
3×4+1
5 Simplify 3\times 43×4 to 1212
\frac{38}{3}\times \frac{12+1}{4}
3
38
×
4
12+1
6 Simplify 12+112+1 to 1313
\frac{38}{3}\times \frac{13}{4}
3
38
×
4
13
7 Use this rule: \frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}
b
a
×
d
c
=
bd
ac
\frac{38\times 13}{3\times 4}
3×4
38×13
8 Simplify 38\times 1338×13 to 494494
\frac{494}{3\times 4}
3×4
494
9 Simplify 3\times 43×4 to 1212
\frac{494}{12}
12
494
10 Simplify
\frac{247}{6}
6
247
11 Convert to mixed fraction
41\frac{1}{6}41
6
1
41 and 1/6
<em>ANSWER :</em>
<u><em></em></u>
<em>I THINK ITS B </em>
<u><em></em></u>
EXPLANATION :
<u><em>ANSWERED BY THE BEST !!!!</em></u>
<u><em></em></u>
<em> </em><u><em>ANGIEEEEEE <3 </em></u>
<u><em></em></u>
<em>HOPE YOU DO WELL ON YOUR ASSIGNMENT !!!!! <3</em>
Answer:
Step-by-step explanation:
pyramid has a height of 5 inches and a volume of 60 cubic inches. Select all figures that could be the base for this pyramid.
A:
a square with side length 6 inches
B:
a 3 inch by 4 inch rectangle
C:
a 4 inch by 9 inch rectangle
D:
a circle with radius 4 inches
E:
a right triangle with one side 5 inches and the hypotenuse 13 inches
F:
a hexagon with an area of 36 square inches