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Travka [436]
2 years ago
10

The mean life time of sample of 100 fluorescent light bulbs produced by a company is computed to be 1570 hours with a standard d

eviation of 120 hours. The company claims that the average life of the bulbs produced by it is 1600 hours. Using the level of significance of 0.05, is the claim acceptable? ​
Mathematics
1 answer:
inessss [21]2 years ago
7 0

Answer:

The mean lifetime of a sample of 100 fluorescent light bulbs produced by a company is

The mean lifetime of a sample of 100 fluorescent light bulbs produced by a company is computed to be 1570 hours with a standard deviation of 120 hours.

Step-by-step explanation:

https://www.cs.bu.edu/faculty/snyder/cs237/Handouts%20and%20Web%20Documents/Handouts/PracticeProblemsHypothesisTesting.pdf

Have a bless day

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<h2>Explanation:</h2>

Here we have the following expression:

3\sqrt{22}\sqrt{58}\sqrt{18}

So we need to simplify that radical expression. By property of radicals we know that:

\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}

So:

3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}

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Hence:

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By property:

\sqrt[n]{a^n}=a

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3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}

Finally:

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

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