Question

HURRY PLEASE

Answer 1

To find the Probability of C given that you have only Y to choose from you need to only use the Y values on the table.  C has a total of 15 in the Y column and total Y is 30.  So P(c given y) is just 15/30 or .5

Answer 2

Answer-

P(C|Y) of the information in the table was found to be 0.5

Solution-

We know from the formula for conditional probability that,

$P(B\mid A)=\frac{P(A \ and \ B)}{P(A)}$

Applying the same,

$P(C\mid Y)=\frac{P(C \ and \ Y)}{P(Y)}$

Calculating the values,

$Probability \ of \ an \ event =\frac{favorable \ outcomes}{possible \ outcomes}$

$P(C)=\frac{40}{146}=\frac{20}{73} \ and \ P(Y)=\frac{30}{146}=\frac{15}{73}$

$P(C \ and \ Y)=\frac{15}{146}$

$\therefore P(C\mid Y)=\frac{\frac{15}{146}}{\frac{15}{73}} =\frac{73}{146} =0.5$