Answer:
6. 3x^3-7x^2+4x-1
7. -6x^4-2x^2+6x+10
8. 42x^4
Step-by-step explanation:
Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Angles 2, 6, and 7 because angle 1 = 115 so that makes angle 4 = 115 so angle 2 must also be 65 so angle 4 and 2 = 180 and the same goes for angles 5,6,7,8
10 apples..........................................
