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3 years ago

Arrange this letters plss

Chemistry

1 answer:

Bingel [31]3 years ago

6 0

Answer: 1 . Unsaturated Solution

2. Saturated Solution

Explanation:

1 ..tedsaturauntionsolu----------- Unsaturated Solution

2. ratedsatulutisoon--------------Saturated Solution

An Unsaturated solution is defined as a solution which contains an amount of solute that dissolves completely since the amount of solute is still less than the maximum amount that can readily dissolve in such solution and an additional amount of solute if added continues to dissove in the solution. Here the solution is still less than the equilibrium point.

example include. Addition of salt or sugar in water and it dissoves completely.

A saturated solution is defined as A solution which contains a maximum amount of solute that an additional solute will no longer be capable of being dissolved further since its equilibrium point has been reached.

Example- The addition of sugar to water till it no longer dissolves

Carbonated water is a saturated solution saturated with carbon as can be seen in the air bubbles it gives offf in form of carbon.

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Calculate the pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl .

Nitella [24]

Answer: 7

Explanation:

50 ml 0.125 M KOH = (50 * 0.125) = 6.25 ml 1 M KOH

similarly 50 ml 0.125 M HCl = 6.25 ml 1 M HCl

so KOH will fully neutralize the HCl so the pH of the medium will be 7

H+ + OH- = H2O

so Kw = [H=][OH-]

= [H+]^2 = 10-14

SO [H+] = 10-7

pH = -log [H+]

pH = -log[10-7]

pH = 7

6 0

3 years ago

Analyze the following reaction and the given scenarios to discuss the relationship between volume and reaction rate. Determine w

vredina [299]

The second reaction with the volume of 5L will occur faster as compared to the first reaction of volume 10L.

Volume is inversely proportional to the rate of reaction.

As volume increases rate of reaction decreases and as volume decreases rate of reaction increases.

Let's consider a reaction A → B.

r is rate of reaction and K is rate constant, A is the concentration of reaction.

r = k(A)

r is directly proportional to the A.

But the concentration of A is in Moles/liters (i.e. moles per unit volume)

r is inversely proportional to the volume of vessel or chamber.

Hence as volume increases rate of reaction decreases.

For study more about reaction rate refer following link brainly.com/question/19513092.

#SPJ1.

5 0

2 years ago

Help me now, please!

Nikitich [7]

Answer:

1. SnO2 = 1; H2 = 2; Sn = 1; H2O = 2

2. I mole of SnO2 is required to react with 2 moles of H2 to produce 1 mole of Sn and 2 moles of H20.

The balanced equation represents 1 mole of SnO2

3. Total mass of reactants and products are each 154.71g respectively

Explanation:

1. According to the law of conservation of mass, the total mass of reactants in a chemical reaction is equal to the mass of products.

Therefore, a balanced chemical equation has equal number of moles of each atom on the reactants side and on the product side. The balanced chemical equation for the reaction above will be:

Sn02 + 2H2 + Energy -----> Sn + 2H2O

Sn has 1 mole of atoms on both sides

O has 2 moles of atoms on both sides

H has 4 miles of atoms on both sides.

2. According to the balanced chemical equation above,

1 mole of SnO2 reacts with 2 moles of H2 to produce 1 mole of An and 2 moles of H20.

This balanced equation represents 1 mole of SnO2.

3. The atomic masses of Sn, O and H are 118.71g, 16g and 1g respectively.

Therefore, the molar masses of the reactants and products are;

SnO2 = 118.71 + 16 * 2 = 150.72g

H2 = 2 *1 = 2g

H2O = 2 * 1 + 16 = 18g

Total mass of reactants = 150.71g + 2 * 2g = 154.72g

Total mass of products = 118.71 + 2 * 18g = 154.71g

3 0

3 years ago

The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?

AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0

4 years ago

What is the appropriate chemical formula for Iron(III) Sulfate? Sulfate is SO_4^2 Fe3SO4 O a . Fe2(SO4)3 O b. O c. Fe2SO4 O d. F

AnnyKZ [126]

<u>Answer:</u> The chemical formula of Iron (III) sulfate is $Fe_2(SO_4)_3$

<u>Explanation:</u>

Iron is the 26th element of periodic table having electronic configuration of $[Ar]3d^64s^2$ .

To form $Fe^{3+}$ ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of $SO_4^{2-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is $Fe_2(SO_4)_3$

4 0

3 years ago