Question

Electrolysis of molten NaCl in a Downs cell is the major isolation step in the production of sodium metal (Section 22.4). Assuming that 215 g of Na metal forms,(c) How many amps will produce this amount in 9.50 h?

Answer 1

The current produced in 9.50 h is 26.37 A

How to find the number of moles?

To find the number of moles use this formula

Number of moles = $\frac{\text{Given mass}}{\text{Molar mass}}$

Number of Moles = $\frac{215}{22.98}= 9.352 mol Na$

Now,

$Current = \frac{Charge}{Time}$

Assuming 215 g of metal forms:

Thus,

Charge = $Moles- e^{-} * F$

Charge = 9.02 × 10⁵ C

Convert 9.5 hours into seconds.

9.5 × 60 × 60 = 34200 Sec

Current = $\frac{Charge}{Time}$

Current =  $\frac{9.02 \times 10^{5} }{34200}$

             = 26.37 A

Thus from the above conclusion we can say that 26.37 A will produce this amount in 9.50 h.

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