Answer:
2914 J
Explanation:
Step 1: Given data
- Mass of the copper tubing (m): 665.0 g
- Initial temperature: 15.71 °C
- Final temperature: 27.09 °C
- Specific heat of copper (c): 0.3850 J/g.°C
Step 2: Calculate the temperature change
ΔT = 27.09 °C - 15.71 °C = 11.38 °C
Step 3: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.3850 J/g.°C × 665.0 g × 11.38 °C
Q = 2914 J
Answer:
The specific heat capacity of a metal is 1.31 J/g°C = C
Explanation:
A classical excersise of calorimetry to apply this formula:
Q = m . C . ΔT
177.5 J = 15 g . C (34°C - 25°C)
177.5 J = 15g . 9°C . C
177.5 J /15g . 9°C = C
1.31 J/g°C = C
Answer:
The answer is "
"
Explanation:
The water solution of PbCl2 is poor. It also has 2 distinct dissolving properties. In cold water, this will not dissolve easily.It is water-insufficiently soluble. And that in cold water, it is indeed insoluble. That's why we know that all energy should be available for a solid to dissolve in the liquid to counteract that attractive force between the ions in the grid.
Answer:
The initial temperature was 58.4°C
Explanation:
Given the following data:
initial volume = V₁ = 380 mL = 0.38 L
final volume = V₂ = 250 mL = 0.25 L
final temperature = T₂ = -55°C = 218 K
According to Charles's law, the volume of a gas is <em>directly proportional to the temperature</em> (in Kelvin). The mathematical expression is:
V₁/T₁= V₂/T₂
So, we calculate the initial temperature (V₁) as follows:
T₁ = T₂/V₂ x V₁ = 218 K/(0.25 L) x 0.38 L = 331.36 K ≅ 331.4 K
Finally, we convert the initial temperature from K to °C:
T₁= 331.4 K - 273 = 58.4°C
The total mass is the sum of the masses.
It is
5543 + 23.45 + 697.4 mg = 6263.85 mg
Answer: 6263.85 mg
