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4 years ago

Which ordered pair is a solution of the equation y=x-4

Mathematics

2 answers:

AlexFokin [52]4 years ago

8 0

Answer:

Step-by-step explanation:

y = x - 4

there are so many ordered pairs which are the solution of the given equation.

for example,

x = 0, y = -4

x = 1 , y = -3

x = 2, y = -2

x = 3, y = -1

x = 4, y = 0

x = - 1, y = - 5

x = - 2, y = - 6

x = - 3, y = - 7

x = - 4, y = - 8

Andreyy894 years ago

5 0

The answer would be y=-4 and x=4, so pick which ever number/letter has this answer.

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EastWind [94]

The given equation is,

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Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

$\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}$

Now, group the like terms.

$-3n+5n-2n+12=0$

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$\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}$

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Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

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The option (c) is "infinitely many solutions".

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1 year ago

Find the common difference if the 8th term is 55 and the first term is 13

Vlad [161]

Answer:

Step-by-step explanation:

Equation

L = a + (n - 1)*d

Givens

L = 55

a = 13

n =8

Solution

55 = 13 + (8 - 1)*d Combine

55 = 13 + 7d Subtract 13 from both sides

55 - 13 = 7d

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3 years ago

At what value of x does the graph of the following function F(x) have a

tankabanditka [31]

Given:

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To find:

The vertical asymptote of the given function.

Solution:

Vertical asymptote are the vertical line passes thought the values for which the function is not defined.

To find the vertical asymptote, equate the denominator equal to 0.

We have,

$F(x)=\dfrac{1}{x+2}$

Denominator is (x+2).

$x+2=0$

$x=-2$

The vertical asymptote is $x=-2$ .

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