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n200080 [17]
3 years ago
5

Please help im stuck on this question! :)​

Mathematics
1 answer:
nydimaria [60]3 years ago
7 0

Answer:

The answer is 6 (:

Step-by-step explanation:

88-4=84

8+6=14

84 divied by 14= 6

hope this helps! <3

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Easy question:
Delvig [45]

Answer:

3 hours and 45 minutes

Step-by-step explanation:

let's assume the tank has a volume of x liters.

let's assume the speed of filling it is x/6 liters per hour for A and x/10 liters per hour for B.

the formula to calculate the time is:

time = volume / speed

If the pumps work together, the total speed is x/6 + x/10, which is 16/60 x

So the time this takes is:

time = x / (16/60 x) = 60/16 hours = 3.75 hours = 3 hours and 45 minutes.

8 0
2 years ago
To decorate a cake, you make a shade of green icing using 3 drops of yellow food coloring for every 4 drops of blue food colorin
SVETLANKA909090 [29]
This kinda easy. Every 3 yellow drops is 4 blue drops, so here's the answer.        3 = 4, 6 = 8, 9 = 12, 12 = 16. so you would need 16 blue drops.        
5 0
3 years ago
SHOW WORK
mote1985 [20]
1). The answer is 86. .29n =24.94
In order to obtain this you need to divide both sides by .29

2) The answer is 25%
35/140 x 100% =25%

3) The answer is $70
So if 100% of 40 is 40 and 75% of 40 is 30 than you need to add 40 + 30 which equals 70.

Hope this helps :)
4 0
3 years ago
On a coordinate grid, point A is located in the first quadrant. Point B is located at (2, - 1/2
Nookie1986 [14]

Answer:

It's where point B is at (2,0.5)

8 0
2 years ago
solve the given matrix equation for X. Simplify your answers as much as possible. (In the words of Albert Einstein, "Everything
vova2212 [387]

a.

XA^{-1}=A^3

(XA^{-1})A=A^3A

X(A^{-1}A)=A^4

X=A^4

b.

AXB=(BA)^2

A^{-1}(AXB)B^{-1}=A^{-1}(BA)^2B^{-1}

(A^{-1}A)X(BB^{-1})=A^{-1}(BA)^2B^{-1}

X=A^{-1}(BA)^2B^{-1}

c.

(A^{-1}X)^{-1}=(AB^{-1})^{-1}(AB^2)

X^{-1}A=(BA^{-1})(AB^2)

X^{-1}A=B(A^{-1}A)B^2

X^{-1}A=B^3

(XX^{-1})A=XB^3

XB^3=A

X(B^3(B^3)^{-1})=A(B^3)^{-1}

X=A(B^3)^{-1}

d. Not totally sure what the equation is supposed to be, but I guess it's

ABXA^{-1}B^{-1}=A

ABX(BA)^{-1}=A

((AB)^{-1}(AB))X((BA)^{-1}(BA))=(AB)^{-1}A(BA)

X=(AB)^{-1}A(BA)

X=(B^{-1}A^{-1})A(BA)

X=B^{-1}(A^{-1}A)(BA)

X=(B^{-1}B)A

X=A

7 0
3 years ago
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