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Volgvan
2 years ago
13

What's the domain and range?

Mathematics
1 answer:
SOVA2 [1]2 years ago
3 0

The domain and the range of the graph are {-3,-2,0,2,3} and {-6,-5,-2,3,5}, respectively.

<h3>What is the domain and range of a function?</h3>

The domain of a function is the set of x values for which it is defined, whereas the range is the set of y values for which it is defined.

The domain of the given graph are the values of the x-coordinate that the function can take. Therefore, the domain of the given graph is,

Domain: {-3, -2, 0, 2, 3}

The range of the given graph are the values of the y-coordinate that the function can take. Therefore, the range of the given graph is,

Range: {-6, -5, -2, 3, 5}

Hence, the domain and the range of the graph are {-3,-2,0,2,3} and {-6,-5,-2,3,5}, respectively.

Learn more about Domain and Range here:

brainly.com/question/1632425

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One of Tyler’s chores is to feed the chickens. Two bags of chicken feed will last 5 days. How many days will 8 bags of chicken f
aleksley [76]

Answer:

20days

Step-by-step explanation:

1 bag feed : 5/2 = 2.5 days

8 bags feed : 2.5*8 = 20 days

5 0
3 years ago
tank a has 100 gallons of water and is being filled at a rate of 2 gallons per hour. tank b has 140 gallons and is being drained
Artist 52 [7]

Answer:

5 hours must pass

Step-by-step explanation:

Graph the equations y = 2x + 100 and y = -6x + 140

Then find the x intercept of their intersection, in this case, that is 5

5 0
2 years ago
If CB 1 AB and mA = 60, what is the measure of C?
Yanka [14]

Answer:

The answer should be D. 120 degrees

5 0
3 years ago
I need the whole solution
ddd [48]

Confused what the question is. Are you looking for the product or the zeroes?

If you are looking for the product, then:

Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)

= sec² + sec²csc² - 1 + csc²

= sec²csc² + sec² + csc² - 1

= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)

= sec²csc²

Answer: sec²csc²

***************************************************

If you are looking for the zeroes, then:

Using the zero product property, set each factor equal to zero and solve.

<u>First factor:</u>

sec²Θ - 1 = 0

sec²Θ = 1

secΘ = 1, -1

remember that secΘ is \frac{1}{cos}

\frac{1}{cos} = 1 \frac{1}{cos} = -1

cross multiply to get:

cosΘ = 1 cosΘ = -1

use the unit circle (or a calculator) to find that Θ = 0 and π

<u>Second factor:</u>

1 - csc²Θ = 0

1 = csc²Θ

1, -1 = cscΘ

remember that cscΘ is \frac{1}{sin}

\frac{1}{sin} = 1 \frac{1}{sin} = -1

cross multiply to get:

sinΘ = 1 sinΘ = -1

use the unit circle (or a calculator) to find that Θ = \frac{\pi}{2} and \frac{3\pi}{2}

Answer: 0, π, \frac{\pi}{2} , \frac{3\pi}{2}

7 0
3 years ago
If hot and cold water taps are turned on altogether, a bath is filled in three minutes but if the cold tap was only half opened
Anvisha [2.4K]

9514 1404 393

Answer:

  12 minutes

Step-by-step explanation:

Let c and h represent the filling times for the cold and hot taps, respectively. When the cold tap is 1/2 open, we presume that means the filling time becomes 2c.

In terms of baths per minute, the relationships are ...

  1/c + 1/h = 1/3

  1/(2c) +1/h = 1/(3 +1.8) . . . . . 1:48 min:sec is 1.8 minutes

Subtracting the first equation from twice the second, we get ...

  2(1/(2c) +1/h) -(1/c +1/h) = 2(1/4.8) -(1/3)

  1/h = 2/4.8 -1/3 = 1/12

  h = 12

It takes the hot tap 12 minutes to fill the tub alone.

3 0
3 years ago
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