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2 years ago

What's the domain and range?

Mathematics

1 answer:

SOVA2 [1]2 years ago

3 0

The domain and the range of the graph are {-3,-2,0,2,3} and {-6,-5,-2,3,5}, respectively.

<h3>What is the domain and range of a function?</h3>

The domain of a function is the set of x values for which it is defined, whereas the range is the set of y values for which it is defined.

The domain of the given graph are the values of the x-coordinate that the function can take. Therefore, the domain of the given graph is,

Domain: {-3, -2, 0, 2, 3}

The range of the given graph are the values of the y-coordinate that the function can take. Therefore, the range of the given graph is,

Range: {-6, -5, -2, 3, 5}

Hence, the domain and the range of the graph are {-3,-2,0,2,3} and {-6,-5,-2,3,5}, respectively.

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the sum of three integers is 92. the second number is three times the first number. the third number is ten less than twice the

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2 years ago

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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.

Paul [167]

Answer:

1.60 $ft^{2}$

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = $\pi$ $r^{2}$

So that,

for the inner part of the pipe,

r = $\frac{diameter}{2}$

= $\frac{5}{2}$

= 2.5 feet

Area of the inner part of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.5)^{2}$

= 19.625

Are of the inner part of the pipe is 19.63 $ft^{2}$ .

Total diameter of the pipe = 5 + 0.2

= 5.2 feet

r = $\frac{5.2}{2}$

= 2.6 feet

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= 3.14 x $(2.6)^{2}$

= 21.2264

Area of the pipe is 21.23 $ft^{2}$ .

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= 21.2264 - 19.625

= 1.6014

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2 years ago