If you follow a similar approach by drawing a line through point C that is perpendicular to and using the associated defects for
∠A or ∠B instead of ∠C, what are the resulting equations? (Do not go through the complete derivation again, just think about the result you came up with in question 9 and what similar formulas for ∠A or ∠B would look like.)
1 answer:
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Answer:
5
Step-by-step explanation:
Special triangle. 1:1: