Ask question

Ask question

All categories

r-ruslan [8.4K]

2 years ago

11

Solve photo question. Mathematics. Please. Easy one. And last one.

2 answers:

Archy [21]2 years ago

5 0

Answer:

18 nickels and 35 dimes

Step-by-step explanation:

4.40

35 dimes

$3.50

4.40-3.50=0.9

0.9/ 0.05= 18 nickels

There would be 35 dimes and 18 nickels.

Elan Coil [88]2 years ago

4 0

A collection of nickels and dimes is worth $4.40. There are 53 coins in all. How many nickels are there?

Nickel is a US coin worth 5 cents or 0.05.
Dime is a US coin worth 10 cents or 0.10

n + d = 53
0.05n + 0.10d = 4.40

n = 53 - d
0.05(53 - d) + 0.10d = 4.40
2.65 - 0.05d + 0.10d = 4.40
0.05d = 4.40 - 2.65
0.05d = 1.75
d = 1.75 / 0.05
d = 35

n = 53 - d
n = 53 - 35
n = 18

There are 18 nickels and 35 dimes.

0.05n + 0.10d = 4.40
0.05(18) + 0.10(35) = 4.40
0.90 + 3.5 = 4.40
4.40 = 4.40

You might be interested in

What is the cube of 8?<br> O A. 2<br> O B. 64<br> C.53<br> O D. 24

VMariaS [17]

Answer:

for my answer i got 512 but it is not one of the answer choices

Step-by-step explanation:

8 0

2 years ago

Mario was making cookies. He mixed 2½ cups of flour, 1¼ cups of sugar and ½ cup of brown sugar together in a bowl. How many cups

STatiana [176]

Answer:

4 1/4

Step-by-step explanation:

2 1/2 + 1 1/4 + 1/2 = 5/2 + 5/4 + 1/2

LCM = 4

5/2 x 2/2 = 10/4

5/4 = 5/4

1/2 x 2/2 = 2/4

10/4 + 5/4 + 2/4 = 17/4

= 4 1/4

Therefore he put 4 1/4 cups altogether.

7 0

2 years ago

Please help me. I'm going to fail if someone doesn't and quick please.

Ainat [17]

Answer:

D

Step-by-step explanation:

To find volume, you have to multiply all the given sides. Therefore, 14 x 5 x 6 = 2,100. (5 x 6=30 x 14=2100)

7 0

3 years ago

30000 is blank times as much as 30

Sindrei [870]

1000 is the answer !

8 0

3 years ago

Read 2 more answers

A positive integer from one to six is to be chosen by casting a die. Thus the elements c of the sample space C are 1, 2, 3, 4, 5

Alex_Xolod [135]

Answer with Step-by-step explanation:

We are given that six integers 1,2,3,4,5 and 6.

We are given that sample space

C={1,2,3,4,5,6}

Probability of each element= $\frac{1}{6}$

We have to find that $P(C_1),P(C_2),P(C_1\cap C_2) \;and\; P(C_1\cup C_2)$

Total number of elements=6

$C_1$ ={1,2,3,4}

Number of elements in $C_1$ =4

$P(E)=\frac{number\;of\;favorable \;cases}{Total;number \;of\;cases}$

Using the formula

$P(C_1)=\frac{4}{6}=\frac{2}{3}$

$C_2$ ={3,4,5,6}

Number of elements in $C_2$ =4

$P(C_2)=\frac{4}{6}=\frac{2}{3}$

$C_1\cap C_2$ ={3,4}

Number of elements in $(C_1\cap C_2)=2$

$P(C_1\cap C_2)=\frac{2}{6}=\frac{1}{3}$

$C_1\cup C_2=$ {1,2,3,4,5,6}

$P(C_1\cup C_2)=\frac{6}{6}=1$

4 0

3 years ago