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3 years ago

Solve photo question. Mathematics. Please. Easy one. And last one.

Mathematics

2 answers:

Archy [21]3 years ago

5 0

Answer:

18 nickels and 35 dimes

Step-by-step explanation:

4.40

35 dimes

$3.50

4.40-3.50=0.9

0.9/ 0.05= 18 nickels

There would be 35 dimes and 18 nickels.

Elan Coil [88]3 years ago

4 0

A collection of nickels and dimes is worth $4.40. There are 53 coins in all. How many nickels are there?

Nickel is a US coin worth 5 cents or 0.05.
Dime is a US coin worth 10 cents or 0.10

n + d = 53
0.05n + 0.10d = 4.40

n = 53 - d
0.05(53 - d) + 0.10d = 4.40
2.65 - 0.05d + 0.10d = 4.40
0.05d = 4.40 - 2.65
0.05d = 1.75
d = 1.75 / 0.05
d = 35

n = 53 - d
n = 53 - 35
n = 18

There are 18 nickels and 35 dimes.

0.05n + 0.10d = 4.40
0.05(18) + 0.10(35) = 4.40
0.90 + 3.5 = 4.40
4.40 = 4.40

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Measure of a triangle’s side

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Answer
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3 years ago

Assume that Santa has to deliver presents to almost 22 million kids an hour on the night before Christmas. What is his delivery

DENIUS [597]

Answer:

It's about 6,111 kids per second.

Step-by-step explanation:

1 hour = 60 minutes

1 minute = 60 seconds

60*60=3600

1 hour = 3600

hourly rate -> 22,000,000 kids/hr

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secondly rate -> 6,111 kids/second

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3 years ago

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sergejj [24]

Answer:

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Step-by-step explanation:

210.84 - 40.00

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170.84 + 90.05

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6 0

3 years ago

Read 2 more answers

Two brothers want to share a large field equally.

Elan Coil [88]

Yes, the partition gives the two brothers equal shares.

Step-by-step explanation:

Step 1:

Assume the entire field has an area of B. So one brother takes $\frac{1}{12} B$ , $\frac{1}{6}B$ , and $\frac{1}{4} B$

So we need to calculate how much this brother takes in terms of B.

To do this we calculate how much $\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B$ is.

Step 2:

To add $\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B$ ,

First take the LCM of the denominators 12, 6, and 4

The LCM is 12, we multiply the denominator to get the LCM value, this same value is multiplied to the numerator too.

$\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B = \frac{1(1)}{12(1)} B + \frac{1(2)}{6(2)} B + \frac{1(3)}{4(3)} B \\\\\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B= \frac{1B +2B+3B}{12} = \frac{B}{2}$