Solve the following system:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4
In the first equation, look to solve for x:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4
1.8 x - 0.5 y = (9 x)/5 - y/2 and -6.4 = -32/5:
{(9 x)/5 - y/2 = -32/5
Add y/2 to both sides:
{(9 x)/5 = 1/10 (5 y - 64)
{0.6 x + 2.1 y = 2.4
Multiply both sides by 5/9:
{x = 1/18 (5 y - 64)
{0.6 x + 2.1 y = 2.4
Substitute x = 1/18 (5 y - 64) into the second equation:
{x = 1/18 (5 y - 64)
{2.1 y + 0.0333333 (5 y - 64) = 2.4
2.1 y + 0.0333333 (5 y - 64) = 2.1 y + (0.166667 y - 2.13333) = 2.26667 y - 2.13333:
{x = 1/18 (5 y - 64)
2.26667 y - 2.13333 = 2.4
In the second equation, look to solve for y:
{x = 1/18 (5 y - 64)
{2.26667 y - 2.13333 = 2.4
2.26667 y - 2.13333 = (34 y)/15 - 32/15 and 2.4 = 12/5:
(34 y)/15 - 32/15 = 12/5
Add 32/15 to both sides:
{x = 1/18 (5 y - 64)
{(34 y)/15 = 68/15
Multiply both sides by 15/34:
{x = 1/18 (5 y - 64)
y = 2
Substitute y = 2 into the first equation:
Answer: {x = -3, y = 2
Answer:
The value of two numbers is x=49 and y=26 and the corresponding equation for the given condition is x +y =75
<u>Explanation:</u>
Given:
Sum of two numbers is 75
One number is 23 more than other
To find:
Frame the equation for the above condition and find the value of two numbers.
Solution:
From the given we know that the sum of two numbers is 75
Let x and y be the numbers, such that the equation is framed as
x +y =75
And we also know that one number is 23 more than other, so we can say either x or y has a greater one
Here I say x is 23 more than y such that,
x=23+y
Substitute the value of x in the equation and we know
x + y=75 and x=23+y we get,
23+y+y=75
23+2y=75
2y=75-23
2y=52
y=26
Since x=23+y as already stated we get as
x=23+26=49
Result:
Thus the equation for the above given conditions is x +y =75 and the values of two number is 49 and 26
It will be D. 168 because 7 times -4 = -28 then you times -28 with -6 and it equals 168.
Answer:
the anwser is b
Step-by-step explanation:
it is another word for looping
Answer:
Step-by-step explanation:
start by squaring both sides:
squaring a square root cancels it out:
solve for x by first adding 8 to both sides:
then divide both sides by 3: