Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Divide 13.20 by 6.
6/13.20 = 1/2.2
1 bowl is $2.20
There is no image but I am happy to help if you attach one
Answer:
48
Step-by-step explanation:
821 rounded down to 800
17 rounded up to 20
820/20 =41
20x41=820
17 x 41 = 697
17 x 51 = 867
Midpoints
697+867/2 = 782
41 +51/2 = 46
46 x 17 = 782
47 x 17 = 799
48 x 17 =816
49 x 17 =833
50 x 17 =850
So, the highest number is 48.
The closest we can get is 48 x 17=816 & without going over 821.
