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Galina-37 [17]
3 years ago
9

If the diameter of a circle with a circumference of 19.5 inches is reduced by three, what would be the circumference of the new

circle?
Mathematics
2 answers:
agasfer [191]3 years ago
8 0

Since the circumference of a circle = 19.5 inches

2\Pi r = 19.5

2 \times \frac{22}{7} \times r = 19.5

r = \frac{19.5 \times 7}{22 \times 2}

r = 3.1 inches

So, diameter = 2r = 2 \times 3.1 = 6.2 inches.

Since. the diameter of new circle is reduced by three.

Therefore, D = 6.2-3 = 3.2 inches.

R = 3.2 \div 2 = 1.6 inches

Now, circumference of new circle

= 2 \pi r

= 2 \times \frac{22}{7} \times 1.6

=10 inches

So, the circumference of the new circle is 10 inches.

Elanso [62]3 years ago
3 0

It is given that the circumference of the circle is 19.5 inches. Let the diameter is d inches .

And the formula of circumference is

C= \pi d

Substituting the value of C, we will get

19.5= \pi d
\\
d = \frac{19.5}{ \pi}

When the diameter increased by 3, then the circumference is

C = \pi ( \frac{19.5}{ \pi} +3})=Approx 29 inches

And the circumference , when diameter is increased by 3 is 29 inches .

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|x|+5=18 a. 5 or -5 b.13 or -13 c.18 or -18 d.23 -23
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X+5=18
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so X+5-5=18-5
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if any questions please ask
b. 13
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I have a question about polynomial division it is in the picture
Cloud [144]

To answer this question, we have to do the long division process for polynomials. We can do the operation as follows:

To do this division process, we have:

1. Divide the first term of the dividend by the first element of the divisor. They are:

\frac{-4x^3}{4x^2}=-x

2. Now, we have to multiply this result by the divisor, and the result will change its sign since we have to subtract that result from the dividend as follows:

-x\cdot(4x^2_{}-4x-4)=-4x^3+4x^2+4x

And since we to subtract this result from the dividend, we end up with:

-(-4x^3+4x^2+4x)=4x^3-4x^2-4x

3. Then we have the following algebraic addition:

\frac{\begin{cases}-4x^3+24x^2-15x-15 \\ 4x^3-4x^2-4x\end{cases}}{20x^2-19x-15}

4. Again, we need to divide the first term of the dividend by the first term of the divisor as follows:

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5. And we have to multiply 5 by the divisor, and the result will be subtracted from the dividend:

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Since we have to subtract this from the dividend, we have:

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6. And we have to add this algebraically to the dividend we got in the previous step:

\frac{\begin{cases}20x^2-19x-15 \\ -20x^2+20x+20\end{cases}}{x+5}

And this is the remainder of the division, x + 5.

As we can see from the division process, we got as:

1. The quotient: -x + 5

q=-x+5

2. The remainder: x + 5.

R=x+5

Since we have that the dividend = divisor * quotient + remainder.

Therefore, the result for this division is:

-4x^3+24x^2-15x-15=(4x^2-4x-4)\cdot(-x+5)+(x+5)

4 0
1 year ago
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