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2 years ago

A snow plough has a 3.2m blade set at an angle of 30 degrees How wide a path will the snow plough clear

Mathematics

1 answer:

snow_tiger [21]2 years ago

6 0

Answer:

1.6m

Step-by-step explanation:

The length of the blade is 3.2m

The angle which the blade makes is 30°

Assuming the path of the blade and the length it covers is a right-angled triangle,

The length of the blade is the hypothenus while the path at which it clears is the opposite of the triangle.

See attached document for better illustration.

Using SOHCAHTOA,

Sinθ = opposite / hypothenus

opposite = x

hypothenus = 3.2

θ = 30°

Sin30 = x / 3.2

X = 3.2sin30

X = 3.2 × 0.5

X = 1.6m

The path which the snow plough clears is 1.6m

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Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

Points A, B, C and D have coordinates A(5, 7), B(7, 1), C(17, m) and D(−1, 3). If line

STatiana [176]

Answer:

Step-by-step explanation:

I used a graph

6 0

2 years ago

Read 2 more answers

A flagpole is supported by a wire fastened 60 feet from its base. The wire is longer than the height it reaches on the flagpole.

maxonik [38]

Answer:

135.5ft

Step-by-step explanation:

THIS COMPLETE THE QUESTION

flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.

Let X be the length of the wire

Let y be the height of the pole

X= Y + 14

Y= X -14

We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)

Using Pythagoras theorem

X²= 60² + Y²

X² = 3600 + Y²

if we subsitute for Y we have

X² = 3600 + (X -14)²

X² = 3600 +X² -14X-14X+196

X²-X²+ 28X= 3600+196

28X= 3796

X= 3796/28

=135.5ft

hence length of the wire is 135.5ft

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2 years ago

PLEASE HELP!!!!<br> i need help on all of these but if you only have 1 answer that’s still great

hodyreva [135]

Answer:

n = -6

x = -7

n = 27

Step-by-step explanation:

Question 1

-3n - n + 12 = 36

First we get all the variables to one side using subtraction property of equality.

-3n - n + 12 (-12) = 36 (-12)

-4n = 24

divide by the coefficient of n to isolate the variable

-4n/-4 = 24/-4

n = -6

Question 2

-2x - 3x - 15 = 20

-5x - 15 = 20

-5x = 35

x = -7

Question 3

3 + n/9 = 6

Isolate the n variable

n/9 = 6 - 3

multiply by 9

n = 27

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2 years ago

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A student works for 80 hours each month and plans to work for 5 hours each day, but only on days when scheduled to work. The fun

Greeley [361]

Answer:

C. The value of f (4) is 60, and it represents the number of hours of work remaining for the month after working for 4 days

Step-by-step explanation:

So 5 time 4 equals 20...!

80 minus 20= 60

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3 years ago