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ddd [48]
3 years ago
6

An online store receives customer satisfaction ratings between 000 and 100100100, inclusive. In the first 101010 ratings the sto

re received, the average (arithmetic mean) of the ratings was 757575. What is the least value the store can receive for the 111111th rating and still be able to have an average of at least 858585 for the first 202020 ratings
Mathematics
1 answer:
Monica [59]3 years ago
7 0

Complete question is;

An online store receives customer satisfaction ratings between 0 and 100, inclusive. In the first 10 ratings the store received, the average (arithmetic mean) of the ratings was 75. What is the least value the store can receive for the 11th rating and still be able to have an average of at least 85 for the first 20 ratings?

Answer:

50

Step-by-step explanation:

We are told that In the first 10 ratings the store received arithmetic mean of the ratings = 75.

Thus;

Sum of the first 10 ratings = 75 × 10 = 750

Now, for the mean of the first 20 ratings to be at least 85, it means that the sum of the first 20 ratings would be; 85 × 20 = 1700

Thus, the sum of the next 10 ratings would be; 1700 − 750 = 950.

If maximum rating = 100, then the maximum possible value of the sum of the 12th to 20th ratings is given by;

9 × 100 = 900.

Now, in order to make the store have an average of at least 85 for the first 20 ratings, the least value for the 11th rating is;

950 − 900 = 50

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Find the sum 49+50+51+52+...+141+142
gayaneshka [121]

Answer:

8977

Step-by-step explanation:

Hello,

49+50+51+52+...+141+142\\\\=(48+1)+(48+2)+(48+3)+(48+4)+...+(48+93)+(48+94)\\\\=48\times 94+(1+2+3+4+...+93+94)\\\\=48\times 94 + \dfrac{94\times 95}{2}\\\\=47(48\times 2+95)=47\times 191=8977

thanks

7 0
3 years ago
In a recent year, one United States dollar was equal to about 82 Japanese yen. How many Japanese yen are equal to $100? $1,000?
alexandr402 [8]
Well if $1=82 than $100 (which is 100 times 1) would equal 82·100=8,200
$1,000·82=82,000
$10,000·82=820,000 :) hope this helps!
8 0
3 years ago
Read 2 more answers
I need help with this
klio [65]

i cannot help with all this but 16 would be 33 ft

8 0
3 years ago
TOPIC: AREA OF COMPOSITE FIGURES!!... HELLO!! :) CAN U PLEASE HELP ME WITH THIS PROBLEM? I WILL GIVE YOU BRAINLIEST AND A THANKS
alexandr402 [8]

Answer:

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Step-by-step explanation:

i did this 4 points

8 0
2 years ago
The digits 2 comma 3 comma 4 comma 5 comma and 2, 3, 4, 5, and 6 are randomly arranged to form a​ three-digit number. ​ (Digits
iren2701 [21]
There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60

To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4.  (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4).    (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6

Therefore probability is 6/60 = 1/10.
5 0
3 years ago
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