True they could be congruent by ASA
Answer:
7997.06 is the awnser to the question
Option A:
V = 1/3 * b^2 * h
V = 1/3 * 10.5^2 * 6
V = 1/3 * 110.25 * 6
V = 220.5
Option B:
V = 1/3 * b^2 * h
V = 1/3 * 3.6^2 * 8
V = 1/3 * 12.96 * 8
V = 34.56
Option C:
V = 1/3 * b^2 * h
V = 1/3 * 4.2^2 * 12
V = 1/3 * 17.64 * 12
V = 70.56
Option D:
V = 1/3 * b^2 * h
V = 1/3 * 6^2 * 8.4
V = 1/3 * 36 * 8.4
V = 100.8
I guess it's 'None of the Above'
Answer:
Part A: 3x²(x⁸ - 16)
Part B: 3x²(x² - 2)(x² + 2) (x² - 2x + 2)(x² + 2x + 2)
Step-by-step explanation:
Part A. Factor out the greatest common factor
3x¹⁰ - 48 x²
= 3x²(x⁸ - 16)
Part B. Factor the expression completely
(i) Factor the difference of squares
x⁸ - 16
= (x⁴ - 4)(x⁴ + 4)
= (x² - 2)(x² + 2)(x⁴ + 4)
3x¹⁰ - 48 x² = 3x²(x² - 2)(x² + 2)(x⁴ + 4)
(ii) Factor the sum of squares
Use the Sophie Germain Identity to factor x⁴ + 4.
x⁴ + 4
= (x²)² + 2² (Still a sum of squares)
= (x² + 2)² - 4x² (Factor this as a difference of squares)
= (x² + 2 - 2x)(x² + 2 + 2x)
3x¹⁰ - 48 x² = 3x² (x² - 2)(x² + 2) (x² - 2x + 2)(x² + 2x + 2)
You would multiply the area by the height
Hope this helps
The answer is 2160
