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2 years ago

Simplify the following expression by combining like terms: - 2 +63 +2 - 2x + 8 - 4:

Mathematics

1 answer:

tangare [24]2 years ago

5 0

Answer:

6+4x-3z

Step-by-step explanation:

-2+6x+z-2x+8-4z

6+6x+z-2x-4z

6+4x+z-4z

6+4x-3z

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HELPPP PLSSS ! THANKKKK YOUUU <3

schepotkina [342]

imma go with A 2462

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2 years ago

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Determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions. Afterwards, determin

Serga [27]

Answer:

One Solution

$x = 8$

Step-by-step explanation:

Given

$-10x = -80$

Required

Determine the number of solution and the value of x

The equation is a linear equation and they have just one solution

Solving further [Divide both sides by -10]

$\frac{-10x}{-10} = \frac{-80}{-10}$

$x = \frac{-80}{-10}$

$x = 8$

Hence;

x has only one value

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3 years ago

A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa

UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so $\mu = \frac{14}{60} = 0.2333$

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081$

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0

3 years ago

A box is filled with 10 brown cards , 4 yellow cards, and 4 red cards. A card is chosen at random from the box. What is the prob

Setler [38]

The answer is 2/9

explanation:
10+4+4= 18 cards in the box
and there are 4 red cards in the box, so it’s 4/18. u divide both sides by 2, which gives u the simplest version, 2/9.

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3 years ago

1. 3x + 6y = 3 and 7x + 3y = 7 ons for bo

sweet-ann [11.9K]

Answer:

(1,0)

Step-by-step explanation:

3x + 6y = 3

7x + 3y = 7

Multiply the second equation by -2

-2( 7x + 3y = 7)

-14x -6y = -14

Add this to the first equation to eliminate y

3x + 6y = 3

-14x -6y = -14

--------------------

-11 x = -11

Divide by -11

x = 1

Now find y

3x + 6y = 3

3 +6y = 3

Subtract 3 from each side

6y = 0

y =0

3 0

3 years ago

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