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Art [367]
2 years ago
12

¿Cuál es la expresión algebraica que representa el área sombreada en la siguiente figura?

Mathematics
2 answers:
vfiekz [6]2 years ago
8 0

Answer:

english puk

Step-by-step explana

coldgirl [10]2 years ago
6 0
La respuesta es : 10x + 4

La fórmula para el área sombreada es:

((x + 3) (2x + 1)) - (x (2 x-3)).

Simplificar

(2x ^ 2 + 7x + 4) - (2x ^ 2 -3x).

Sustraer

= 10x + 4
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Answer:

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Step-by-step explanation:

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3 years ago
How many solutions does the system of equations below have?<br> 2x – 3y = -9<br> 4х – бу = -18
HACTEHA [7]

Answer:

2

Step-by-step explanation:

because they have the same symbol which let's them be able to add or sybtract

3 0
2 years ago
A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ
jonny [76]

Let \vec r(t),\vec v(t),\vec a(t) denote the rocket's position, velocity, and acceleration vectors at time t.

We're given its initial position

\vec r(0)=\langle0,0,10\rangle\,\mathrm m

and velocity

\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}

Immediately after launch, the rocket is subject to gravity, so its acceleration is

\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}

where g=9.8\frac{\rm m}{\mathrm s^2}.

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}

\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}

and

\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m

\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m

\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}

b. The rocket stays in the air for as long as it takes until z=0, where z is the z-component of the position vector.

10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}

c. The rocket reaches its maximum height when its vertical velocity (the z-component) is 0, at which point we have

-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)

\implies\boxed{z_{\rm max}=125,010\,\rm m}

7 0
3 years ago
Some adults and children went to a movie.
aalyn [17]
4 adults and 8 children
3 0
3 years ago
Read 2 more answers
The expression m÷4 is the distance each person runs in a relay race that is m miles. How far does each person run in a relay rac
inna [77]

Answer:

5

Step-by-step explanation:

Replace 20 instead of m

20/4=5

5 0
3 years ago
Read 2 more answers
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