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olga2289 [7]
3 years ago
5

What is the domain of the function shown in the graph below?

Mathematics
2 answers:
tigry1 [53]3 years ago
6 0

Answer:

All except one interval [-2,8]

Step-by-step explanation:

Notice that the function, wich an hyperbola, has a vertical asymptote in both -2 and 8 and there is nothing between this two values.

So we will exclude what's between them out of the domain.

Natali [406]3 years ago
5 0

All values except [-2,7]

the graph isn't proper, but it's obvious what the answer would be.

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Are non-empty sets and A × B = B × A then ……
alex41 [277]

Answer:

b

Step-by-step explanation:

dycffffffffhshshshsj

4 0
4 years ago
Solve ALL please . work needed <br><br> 5x-1=x+115<br><br><br> 3+5q=9+4q<br><br><br> 2b+4=-18-9b
spin [16.1K]
1) 5x-1=x+115

5x-x=115+1
4x=116
x=116/4
x=29 (Answer)

2) 3+5q=9+4q

5q-4q=9-3
q=6 (Answer)

3) 2b+4=-18-9b

2b+9b=-18-4
11b=-22
b=-22/11
b=-2 (Answer)

Hope this helps
7 0
3 years ago
angle U and angle W are vertical angles. If measurement angle u = 6x+11 and measurement angle W = 10x-9, find measurement angle
IgorC [24]

The measure of angle U will be equal to the measure of angle W.

Because W is pronounced "double u", W = 2 * U.

Therefore U = W and U = 2 * W, so both U and W = 0.


Just kidding.

The correct answer is the smallest prime number greater than 40.

8 0
3 years ago
Solve both questions please ❤️❤️
harina [27]

Answer:

1. y=7.2

2. x=18

Step-by-step explanation:

1. Triangles CMN and CBA are similar triangles (by AAA postulate). Similar triangles have proportional corresponding sides, so

\dfrac{CM}{CB}=\dfrac{CN}{CA}\\ \\\dfrac{12}{12+y}=\dfrac{10}{10+6}\\ \\12\cdot 16=10\cdot (12+y)\\ \\192=120+10y\\ \\10y=72\\ \\y=7.2

2. GK is angle G bisector. Use angle bisector's property:

\dfrac{GH}{GI}=\dfrac{KH}{KI}\\ \\\dfrac{40}{24}=\dfrac{30}{x}\\ \\40x=24\cdot 30\\ \\4x=24\cdot 3\\ \\x=6\cdot 3=18

8 0
3 years ago
What is the equation of the asymptotes?
alexandr1967 [171]
Vertical Asymptotes:
x
=
7
x
=
7
Horizontal Asymptotes:
y
=
2
y
=
2
No Oblique Asymptotes
3 0
3 years ago
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