Answer:
586
Step-by-step explanation:
First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Answer:
x=4 x=10
Step-by-step explanation:
(x - 6) (x - 8) =8
We need to multiply out the left side
x^2 -8x -6x+48 = 8
x^2 -14x +48 = 8
Subtract 8 from each side
x^2 -14x +48-8 = 8-8
x^2 -14x+40 =0
We need to factor the left side. What two numbers multiply to give 40 and add to give -14
-4*-10 = 40
-4+-10 = -14
(x-4) (x-10) =0
Using the zero product property
x-4=0 x-10 =0
x=4 x=10
