Question

What is the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms? 1,842 1,844 1,846 1,848?

Answer 1

$= \frac{24}{2} (2(8) + 23(6))$
$= 12(16 + 138)$
$= 12(154)$
$= 1848$