Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

Hence the bounds of the interval are:
As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
More can be learned about the z-distribution at brainly.com/question/25890103
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It is given in the question that f is a one-to-one function.
And for a one-to - one function,
If

So we will get

76÷4= ; x=19, you divide 76 by 4 because if he is 1/4 then it would be a group of one of the 4's, thus saying ehen you divide 76 by 4, it equals 19, so he is 19 years old, you could also do 19×4 and 22×4 to see which equals 76.