Im sorry i can’t help you but you can use photomath and also Aaa HANGE
Answer: P(x > - 0.23) = 0.41
Step-by-step explanation:
Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the readings at freezing on a batch of thermometers.
µ = mean temperature reading
σ = standard deviation
From the information given,
µ = 0°C
σ = 1.00°C
the probability of obtaining a reading less than -0.23°C is expressed as
P(x > - 0.23)
For x = - 0.23
z = (- 0.23 - 0)/1 = - 0.23
Looking at the normal distribution table, the probability corresponding to the z score is 0.41
Answer:
Step-by-step explanation:
8×4 = (A×7) - (A×3) = A(7-3) = A×4
A = 8
Answer:
x = 20, <S = 47 degrees, <P = 131 degrees
Step-by-step explanation:
27 + x + 119 + 63 + 3x + 71 = 360
4x + 280 = 360
4x = 80
x = 20
<S = 27 + x = 27 + 20 = 47 degrees
<P = 3x + 71 = 3(20) + 71 = 131 degrees
8 x $9 = $72.00
8 x $3 = $24.00
$72.00 + $24.00 = $96.00
savings changed by $96.00
