If there are 10 balls in a bag and

Mathematics

1 answer:

Vitek1552 [10]3 years ago

3 0

There are 6 red balls

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Write the equation of the line that passes through (3, 4) and ( 2, -1) in slope-intercept form

rjkz [21]

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{3}}}\implies \cfrac{-5}{-1}\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{5}(x-\stackrel{x_1}{3}) \\\\\\ y-4=5x-15\implies y=5x-11$

3 0

3 years ago

Help answer asap pls ---------

Reika [66]

Answer:

d = 5

Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: $\sqrt{8 - (-1)} = 2(-1)+d$ . On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: $\sqrt{9} = d-2$ . We know that $\sqrt{9}$ = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!