If there are 10 balls in a bag and

Mario invested $475 in $45 and $25 stock shares. The number of $25 shares was 5 less than 3 times the number of $45 shares. How

Anit [1.1K]

$\text{Answer : Number of \$45 shares} =120$

$\text{Number of \$25 shares }\\\\= 3\times 120-5\\\\=360-5\\\\=\$355$

Explanation:

Let Number of $45 shares be x

Let number of $ 25 shares be 3x-25

According to question,

$x+3x-5=475\\\\4x-5=475\\\\4x=475+5\\\\4x=480\\\\x=\frac{480}{4}\\\\x=120$

So,

$\text{Number of \$45 shares} =120$

$\text{Number of \$25 shares }\\\\= 3\times 120-5\\\\=360-5\\\\=\$355$

6 0

4 years ago

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A taxi journey of 30km cost $3,600.At the same rate per kilometer .A what would be the cost of travelling 25k.B.How far could yo

madreJ [45]

Answer:

The cost of traveling 25km would be $3000.

You can travel 35 km for $4200.

Step-by-step explanation:

Consider the provided information.

For 30km cost $3,600.

30 km = $3600

Divide both sides by 30.

$\frac{30}{30}\text{ km}=\frac{3600}{30}$

$1 \text{ km} =120$ ....(1)

The cost of 1 km is $120.

Part (A) what would be the cost of traveling 25km

Multiply both the sides of equation 1 by 25.

25 km = 3000

Hence, the cost of traveling 25km would be $3000.

Part(B) How far could you travel for $4,200?

Divide 4200 by 120.

$\frac{4200}{120}=35$

Hence, you can travel 35 km for $4200.

7 0

3 years ago

Simplify the square root of four over the cubed root of four.

Vikki [24]

$\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\\\ ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{\sqrt{4}}{\sqrt[3]{4}}\implies \cfrac{\sqrt[2]{4}}{\sqrt[3]{4}}\implies \cfrac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}\implies 4^{\frac{1}{2}}\cdot 4^{-\frac{1}{3}}\implies 4^{\frac{1}{2}-\frac{1}{3}}\implies 4^{\frac{3-2}{6}} \\\\\\ 4^{\frac{1}{6}}\implies (2^2)^{\frac{1}{6}}\implies 2^{2\cdot \frac{1}{6}}\implies 2\frac{1}{3}\implies \sqrt[3]{2}$

7 0

3 years ago

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Greetings, Agent OOZero. Your mission, if you choose to accept it, is to use the

Olegator [25]

Answer:

Gertrude's favorite is George Burn

What we know from the beginning:

Comedians:

George Burn
Jack Benny
David Letterman
Jerry Springfield

Lucy: Jerry Springfield is her favorite

David: Does not like David Letterman

Gertrude: Does not like David Letterman, Does not like Jack Benny anymore

Solving:

Since we know that Jerry Springfield is Lucy's favorite, he is not longer an option. This leaves George Burn, Jack Benny, and David Letterman.
David and Gertrude do not like David Letterman, so he must be Jose's favorite. This leaves George Burn and Jack Benny
Gertrude does not like Jack Benny anymore, so the only one left to be her favorite is George Burn

7 0

3 years ago

Help again. thanks again for helping me. also take ur time.

gogolik [260]

Answer:

2

Step-by-step explanation:

-10*7.5+115=p

115-75=p

p=40

8 0

3 years ago

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