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2 years ago

A bus travels one and one half miles to a bus stop 4 times. How many miles in all has the bus traveled?

2 answers:

6 0

First you have your two numbers: 1.5 and 4.
The question explains that they travel 1.5 miles 4 times each, meaning you multiply the two.
1.5×4=6

So, your answer is 6 miles.

Hope this helps!

egoroff_w [7]2 years ago

5 0

6 miles! 1.5 +1.5 = 3 and 3+3=6 :$

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Solve each equation. Use models if necessary. Check your solution.

morpeh [17]

so, the right answer is -8.

Look at the attached picture⤴

Hope it will help u...

8 0

3 years ago

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Use the zero product property to find the solution to the equation x^2 +12=7x

pochemuha

X2 + 12 = 7x x2 – 7x + 12 = 0factor the equation (x – 3 ) ( x – 4 ) = 0 Then equating both factor to 0 X – 3 = 0 X = 3 And X – 4 = 0 X = 4 So the answer is X = 3 X =4

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4 years ago

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Simplify 4^2 * 4^8= A.)4^16 B.)4^10 C.)16^16 D.)16^10 please help me i need this asap.

SVEN [57.7K]

Answer:

4^{10}

Step-by-step explanation:

Complete the exponents first.

4*4=16

4*4*4*4*4*4*4*4=65536

65536 *16= 1048576

The answer is $4^{10}$

You can also find this if you add the exponents.

6 0

3 years ago

-5/6+ -5/6 please help me

ehidna [41]

(-5/6)+(-5/6) have the same denominator (number at bottom of fraction), so all you have to do is add the numerator(top number). So -5 +-5 =-10 . Now you have -10/6, which simplifies to -5/3.
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3 years ago

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Listed below are the ACT scores of 40 randomly selected students at a major university. (Use technology if you wish, Excel) 18 1

tiny-mole [99]

Answer:

A) See the picture

B) 14

C) 45%

Step-by-step explanation:

A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable

B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution

Pc1 = 100*(4/40) = 10

Pc2 = 100*(4/40) = 10

Pc3 = 100*(3/40) = 7.5

Pc4 = 100*(11/40) = 27.5

Pc5 = 100*(5/40) = 12.5

Pc6 = 100*(4/40) = 10

Pc7 = 100*(7/40) = 17.5

Pc8 = 100*(2/40) = 5

Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%

Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.

C) Scores equal to or greater than 20 are from class 8 to class 5

Pc8 + Pc7 + Pc6 + Pc5 = 45%

5 0

3 years ago