Since the angle of the arc is 90°, we'll plug that in for theta. We're finding the length of the arc, so we'll use the circumference formula.
Answer:
1.) a
2.) ?
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
come on man if you are in -2 dollar debt and someone gives you 4 more dollars you now have 2 dollars
Poster standard dimension: 8.5 inches by 11 inches
Both length and width of the poster may vary 1/20%
∴ length and width may vary 1/20 % = 0.05% = 0.0005
∵ Area = Width * Length
∴ Area = 8.5 * 11 = 93.5 in²
Smallest acceptable area for one poster:
Width: 8.5 * (1 - 0.0005) = 8.49575 in.
Length: 11 * (1 - 0.0005) = 10.9945 in.
∴ The smallest area = 8.49575 * 10.9945 = 93.4065 ≈ 93.407 in².
