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ollegr [7]
3 years ago
8

Which equation has the same solutions as 2x^2+16x-10=0 a) (x+4)^2=-3 b) (x+4)^2=-11 c) (x+4)^2=13 d) (x+4)^2=21

Mathematics
2 answers:
prisoha [69]3 years ago
5 0
2x^2 + 16x - 10 = 0
2(x^2 + 8x)  - 10 = 0
2 [(x + 4)^2 - 16 ]- 10 = 0
[(x + 4)^2 - 16 - 5 = 0
(x + 4)^2 - 21 = 0
(x + 4)^2 = 21

alekssr [168]3 years ago
4 0
Hello here is a solution : 

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3 years ago
3000 exercise books are arranged into 3 piles. The first pile has 10 more books than the second pile. The number of books in the
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