3 years ago

Which equation has the same solutions as 2x^2+16x-10=0 a) (x+4)^2=-3 b) (x+4)^2=-11 c) (x+4)^2=13 d) (x+4)^2=21

2 answers:

5 0

2x^2 + 16x - 10 = 0
2(x^2 + 8x) - 10 = 0
2 [(x + 4)^2 - 16 ]- 10 = 0
[(x + 4)^2 - 16 - 5 = 0
(x + 4)^2 - 21 = 0
(x + 4)^2 = 21

alekssr [168]3 years ago

4 0

Hello here is a solution :

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