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Anestetic [448]
3 years ago
8

A.)90 B.)41 C.)15 D.)83

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

D

Step-by-step explanation:

∠ABC= ∠DBE (vert. opp. ∠s)

(6x -7)°= (4x +23)°

6x -7= 4x +23

<em>Being</em><em> </em><em>x</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>

6x -4x= 23 +7

<em>Simplify</em><em>:</em>

2x= 30

<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>2</em><em>:</em>

x= 15

<em>Substituting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em>:</em>

m∠ABC

= 6(15) -7

= 83

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22% of all resumes received by a corporation for a management position are from females. 18 resumes will be received tomorrow.
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Answer:

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Step-by-step explanation:

For each resume received by the corporation, there are only two possible outcomes. Either they are from a female, or they are not. The probability of a resume received being from a female is independent from other resumes. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

22% of all resumes received by a corporation for a management position are from females.

This means that p = 0.22

18 resumes will be received tomorrow.

This means that n = 18

What is the probability that exactly 1 resume will be from females?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{18,1}.(0.22)^{1}.(0.78)^{17} = 0.0580

5.80% probability that exactly 1 resume will be from females.

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