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Slav-nsk [51]
3 years ago
11

Arwen uses a dropper that produces drops that have a volume of 1/8 mL to fill a 30 mL test tube how many drops does it take to f

ill the test tube
Mathematics
1 answer:
borishaifa [10]3 years ago
3 0
240 drops. you take 8x1/8=1ml so you have 8 8ths times 30 to give you 240 drops for 30ml test tube

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If f(x) = (x - 1) / (x + 2), then the range of f is given by the interval
Veseljchak [2.6K]

Answer:

B and D

Step-by-step explanation:

Have a great day!

/(OvO)/ *.':☆ *': .✧

3 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!
Zielflug [23.3K]

Answer:

Collisions

Follow Newton’s Third Law which tells us that

the force exerted by body A on body B in a

collision is equal and opposite to the force

exerted on body B by body A.

During a collision, external forces are ignored.

The time frame of the collision is very short.

The forces are impulsive forces (high force, short

duration).

Collision Types

Elastic: P is conserved, K is conserved

Inelastic: P is conserved, K is NOT conserved

Perfectly Inelastic means the bodies stick together

Problem: Collisions (1993)

10. Which of the following is true when an object of

mass m moving on a horizontal frictionless surface

hits and sticks to an object of mass M > m, which is

initially at rest on the surface?

(A) The collision is elastic.

(B) All of the initial kinetic energy of the less-massive

object is lost.

(C) The momentum of the objects that are stuck together

has a smaller magnitude than the initial momentum of

the less-massive object.

(D) The speed of the objects that are stuck together

will be less than the initial speed of the less-massive

object.

(E) The direction of motion of the objects that are stuck

together depends on whether the hit is a head-on

collision.

Explain your reasoning:

Ans. Again, by conservation of momentum, if the

mass increases, the velocity must decrease. pin = pout

Problem: Collisions (1993)

11. Two objects having the same mass travel

toward each other on a flat surface, each with a

speed of 10 meter per second relative to the

surface. The objects collide head-on and are

reported to rebound after the collision, each

with a speed of 20 meters per second relative

to the surface. Which of the following

assessments of this report is most accurate?

(A) Momentum was not conserved, therefore the report is false.

(B) If potential energy was released to the objects

during the collision, the report could be true.

(C) If the objects had different masses, the report could be true.

(D) If the surface was inclined, the report could be true.

(E) If there was no friction between the objects and the

surface, the report could be true.

Explain your reasoning:

Ans. Momentum is conserved provided that an

external force not be applied. If the objects have

potential energy stored, this could provide the force.

PLEASE MARK AS BRAINLIEST!!!!!!

7 0
3 years ago
Can someone help me .
insens350 [35]
Y-y1=m(x-x1)
m= slope =-3
y-y1=-3(x-x1),
y1=-7, x1=5
y--7=-3(x-5)
y+7=-3(x-5) this is C
7 0
3 years ago
The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi
Elan Coil [88]

Answer:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150  

Weight after diet 170 130 215 152

We define the random variable D = before-after and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

And the deviation with:

s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And after replace we got:

\bar D= 7, s_d = 13.638

And the confidence interval for this case would be given by:

\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1= 4-1=3

For the 95% of confidence the value for the significance is \alpha=0.05 and the critical value would be t_{\alpha/2}= 3.182. And replacing we got:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

6 0
3 years ago
I don’t now if u can see it very well but could anyone help me with this
Sauron [17]

Answer:

A and c

Step-by-step explanation:

If im correct A and C is the answer because A and C represent the vertical angles :)

4 0
3 years ago
Read 2 more answers
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