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Aleks [24]
2 years ago
11

0.75:x::5:8, Then find x​

Mathematics
2 answers:
Shalnov [3]2 years ago
8 0

Answer:

Step-by-step explanation:

0.75 :x :: 5: 8

0.75 / x = 5 / 8  

5x = 0.75 * 8

x = 6/5

x = 1.2

lianna [129]2 years ago
3 0

Answer:

1.2

Step-by-step explanation:

0.75 :x :: 5: 8

0.75 / x = 5 / 8

Cross multiply

5x = 0.75 * 8

x = 6/5

x = 1.2

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What is the y-coordinate of the solution to this system of equations?<br> 5x-8y=1<br> 3x+6y=-21
Vanyuwa [196]

5x-8y=1...(1)
3x+6y=-21...(2)

(1)*3:
15x-24y=3...(3)

(2)*5:
15x+30y=-105...(2)

(3)-(2):
15x-24y-(15x+30y)=3-(-105)
15x-24y-15x-30y=108
-54y=108
y=-2
6 0
3 years ago
Can someone help me one these two​
strojnjashka [21]

On the top problem:  Angle A and Angle B are a right angle so it equals 90 degrees.  If Angle B is 50 degrees that makes Angle A 40 degrees.  Angle A and Angle C is a straight line and equals 180 degrees so if Angle A equals 40 degrees that means Angle C equals 140 degrees.

8 0
3 years ago
6:
horrorfan [7]

Step-by-step explanation:

charging the phone for 1 minute ,it has 2%

i.e,1----->2

After 2 minutes from that time ,i.e total 3 minutes

it has 6% charge

i.e,3--------->6

from the both the above cases ,1 minute provide 2%=6/3

=2

Hence,

for getting 50%charge=50/2

=25 min

and,for 90 %charge=90\2

=45 min

8 0
2 years ago
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
11. If Sally
Delvig [45]

Answer:

0.2

Step-by-step explanation:

Multiply 4/5 and 1/4: Decimal form

.8 • .25

3 0
3 years ago
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