Question

F(x) =

Answer 1

9514 1404 393

Answer:

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Step-by-step explanation:

The applicable derivative formula is ...

  d(u/v) = (v·du -u·dv)/v²

__

  f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²

  f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

__

Similarly, the second derivative is the derivative of f'(x).

  f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴

  f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³