The time of flight of a half projectile motion is given by V0 sin θ / g = 15(sin 45) / 9.8 = 1.08 seconds.
Answer:
Step-by-step explanation:
10kw/h in a day it will be
10kw*24h=240kw/day
240*4=960 kw/ day for 4 turbines
Let the time taken to finish the test be x.
P(50 < x < 60) = P(x < 60) - P(x < 50) = P(z < (60 - 60)/10) - P(z < (50 - 60)/10) = P(z < 0) - P(z < -1) = P(z < 0) - (1 - P(z < 1)) = P(z < 0) + P(z < 1) - 1 = 0.5 + 0.8413 - 1 = 0.3413
14 and 15
14^2 = 196
15^2 = 225
225+196 = 421
40(8) + (2(12))(8) + 200
320 + 24(8) + 200
520 + 192
712
Answer: B. 712
