Step-by-step explanation:
<em>1</em><em>1</em><em>)</em><em> </em><em>PnQ</em><em>=</em><em>QnP</em>
<em>or</em><em>,</em><em> </em><em>{</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>}</em><em>n</em><em>{</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em><em> </em><em>=</em><em> </em><em>{</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em><em> </em><em>n</em><em>{</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>}</em>
<em>or</em><em>,</em><em> </em><em>{</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>}</em><em> </em><em>=</em><em> </em><em>{</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>}</em><em> </em><em>.</em><em>Ans</em>
Since she already owns one, and they are priced for 2 for a dollar. She would only need to spend $2 dollars to have for and then she will have 5 in total.
Answer:
Angle number 5 is adjacent to angle psl
Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!
Answer: the answer is A
Step-by-step explanation:
