<h2>
Answer:</h2>
m∠MLQ = 60°. (<u>Equilateral triangle</u>)
Hence, m∠QLP = 30°.
<u>ΔLQP is an isosceles triangle (LQ and LP are congruent)</u>
m∠LPQ = m∠LQP = (180 - 30)/2
m∠LQP = 150/ 2
m∠LQP = 75°.
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Answer:
(–1, 1) and (4, –2)
Step-by-step explanation:
we know that
The vertex of the right angle of the triangle could be situated at a point with the same x-coordinate of point A and the same y-coordinate of point B or at a point with the same x-coordinate of point B and the same y-coordinate of point A
we have
A(4, 1) and B(–1, –2)
so
a point with the same x-coordinate of point A and the same y-coordinate of point B is the point (4,-2)
a point with the same x-coordinate of point B and the same y-coordinate of point A is (-1,1)
therefore
(–1, 1) and (4, –2)