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maria [59]
2 years ago
13

"This summer, the water level of Lake Conroe changed by a rate of -1.5 feet per month. The water level at the beginning of May w

as 187 feet above sea level. What was the water level at the end of four months?" heelpppp asaapp
Mathematics
1 answer:
Verdich [7]2 years ago
8 0

Answer:

181 feets

Step-by-step explanation:

Given that:

Rate of change in water level = - 1.5 feets per month

Water level at beginning of May = 187 feets above sea level

Water level at the end of 4 months =?

Total change after four months = rate of change per month * number of months

= - 1.5 * 4 = - 6 feets

Hence water level after 4 months :

187 feets + (-6 feets)

187 feets - 6 feets

= 181 feets

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4. A horizontal ellipse, centered at the origin has a major axis of 10 units and minor axis of 8 units. Write the
s2008m [1.1K]

Answer:

\frac{x^2}{25} +\frac{y^2}{16} =1

Step-by-step explanation:

For ellipses, the length of the major axis is represents as:

Major axis = 2a

where a is called the semi-major axis.

In this case since the major axis is equal to 10 units:

10=2a

solving for the semi-major axis a :

a=10/2\\a=5

and also the minor axis of an ellipse is represented as:

Minor axis = 2b

where b  is called the semi-minor axis.

Since the minor axis has a length of 8 units:

8=2b

solving for b:

b=8/2\\b=4

Now we can use the equation for an ellipse centered at the origin (0,0):

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

and substituting the values for a and b:

\frac{x^2}{5^2} +\frac{y^2}{4^2} =1

and finall we simplify the expression to get the equation of the ellipse:

\frac{x^2}{25} +\frac{y^2}{16} =1

5 0
3 years ago
Find angles in isosceles triangles
Tanzania [10]

Answer - I think the answer is 59

Step-by-step explanation:

6 0
3 years ago
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
3 years ago
I NEED YOUR HELP!!<br> What is 2 + 3x8
Gemiola [76]

Answer:

Don't need Help don't depend on others do you'r work by yourself why you came to this world for asking help from other not do your work by yourself.Today I am going to help but from tomorrow you have to do by yourself

Step-by-step explanation:

=2x+3x8

=add

=5x8

=x=5=8/2

=x=5/4 is your answer

4 0
3 years ago
Read 2 more answers
Collins is working.......
lesya [120]
Let n represent the amount Colin earned on Sunday.

On Sat. he earned n/2; on Sun. he earned n; and on Friday he earned (1/2)(n/2).

Then n/2  +  n  + n/4 = $70

Mult. all terms by 4 to eliminate fractions:

2n + 4n + n = $280

7n = $280  =>  n = $40

Colin earned n/2, or $20, on Saturday; n, or $40, on Sunday; and n/4, or $10, on Friday.

Note that $20 and $40 and $10 add up to $70, as they must.
4 0
3 years ago
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