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Novosadov [1.4K]
3 years ago
15

What is the missing constant term in the perfect square that starts with x2 – 12x ?

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

x^2 -12x+36

Step-by-step explanation:

x^2 – 12x

Take the coefficient of x

-12

Divide by 2

-12/2 = 6

Square it

6^2 = 36

We need to add 36 to make x^2 -12x a perfect square trinomial

x^2 -12x+36

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\begin{bmatrix}-1&-8\\-3&-5\end{bmatrix}\begin{bmatrix}1&3\\8&5\end{bmatrix}\neq \begin{bmatrix}1&3\\8&5\end{bmatrix}\begin{bmatrix}-1&-8\\-3&-5\end{bmatrix}

Therefore, the correct option is B.

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3 years ago
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Step-by-step explanation:

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