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2 years ago

Fred is 4 times as old as Nathan and is also 27 years older than Nathan. Let f be Fred's age and let n be Nathan's age.

Mathematics

2 answers:

otez555 [7]2 years ago

7 0

Nathan is 9 Fred is 36

bazaltina [42]2 years ago

6 0

Answer:

The system of equations is

and

Fred's age is 36 years old and Nathan's age is 9 years old

Step-by-step explanation:

Let

f -----> Fred's age

n ----> Nathan's age

we know that

-----> equation A

----> equation B

equate the equations and solve for n

Find the value of f

therefore

Fred's age is 36 years old and Nathan's age is 9 years old

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Step-by-step explanation:

Given:

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$308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\ Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\ x^{2} +14x+77=0\\ \\ \\$