I had homework on this today lol
First, add 2 to both sides. It would then be 5x = 3x + 10. Then subtract 3x from both sides and you would end up with 2x = 10. Divide 2x by 2 and the 10 by 2. The answer is x = 5.
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Distance = sqrt [ (7.5 - -3.0)^2 + (-7.5 - .5)^2) ]
= sqrt 17,226.56 = 131.25 (answer)
The answer is B. 75 because 105 plus 75 equals 180 degrees...... I used to work on this when I was in 6th grade so it is easy to me hope that helped i tried my best hope you get a 100 hundred as your grade
The answer is = B. 75
