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leva [86]
3 years ago
9

Write a slope-intercept equation for a line that passes through (5,0) and (-3,2)

Mathematics
1 answer:
Tasya [4]3 years ago
6 0

Answer:

Step-by-step explanation:

(x₁,y₁) = (5 , 0)  and (x₂,y₂) = (-3, 2)

Slope= \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

         = \dfrac{2-0}{-3-5}\\\\=\dfrac{2}{-8}\\\\=\dfrac{-1}{4}

Equation of the line : y =mx + b

y = \dfrac{-1}{4}x + b

Plug in x = 5 and y =0 in the above equation.

0 =\dfrac{-1}{4}*5+b\\\\0=\dfrac{-5}{4}+b\\\\b = \dfrac{5}{4}

Equation of the line:

y =\dfrac{-1}{4}x+\dfrac{5}{4}

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Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

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3 years ago
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Answer:

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in this case we have a right angled triangle, whenever you see this triangle think of the TRIG RATIOS * sin, cos & tan* but if it was another triangle besides right angled triangle you use SINE RULE OR COSINE RULE

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