The equation for this line would be y=2x-4
Answer: 0.31
Step-by-step explanation:
Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .
Given : P(A) =0.84 ; P(B)=0.33 and P(A∪B)=0.86
We know that 
Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-

Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31
Answer:

Step-by-step explanation:
[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant
(or, if b is an even number, 1/4 of it) is zero.
<u>I see it! I see it!</u>
Stare at it for a while. First term is
, third term is
, we are missing a double product, but we can play with k. For the LHS to be
you just need
.
<u>I don't see it...</u>
Then number crunching it is. Set the discriminant to 0, solve for k

8-3(p-4)= 2p
⇒ 8 -3p -3(-4)= 2p (distributive property)
⇒ 8 -3p+ 12= 2p
⇒ 8+12= 2p+3p
⇒ 20= 5p
⇒ 20/5= p
⇒ 4= p
Final answer: p=4~