2 years ago

How many real number solutions does the equation y=2x^2−8x+8 have?

Mathematics

1 answer:

Dafna1 [17]2 years ago

6 0

Answer:

1 real solution

Step-by-step explanation:

y=2x^2−8x+8

We can use the discriminant to determine the number of real solutions

b^2 -4ac

a =2 b = -8 c=8

(-8)^2 - 4(2)(8)

64 - 64

Since the discriminant is 0 there is 1 real solution

>0 there are 2 real solutions

< 0 two complex solutions

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