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ANTONII [103]
3 years ago
10

Spends at most 30, buys boxes of crayons that cost 2 per box, also buys a poster for 5. Wants to know how many boxes of crayons

she can spend.
Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

for 15 crayons box she can spend

Step-by-step explanation:

The computation of the number of crayons for which she can spend is shown below:

Given that

She can spend $30

And, the cost is 2 per box

So, for the number of crayons for which she can spend is

= $30 ÷ 2

= 15 crayons box

Hence, for 15 crayons box she can spend

The same would be relevant

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Anvisha [2.4K]

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Step-by-step explanation:

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Write the rule for the function represented by this table.​
sineoko [7]
Rule: y= 3 • x + 1

Explanation

You times a the number shy three then add one
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In the figure below, lines 1 and 2 are parallel. Lines 3 and 4 are also parallel.
attashe74 [19]
I don’t see a diagram, but I assume that you must use these things.

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3 years ago
PLEASE HELP QUICK!!! A bowl has 85 pieces of candy. Nineteen children empty the bowl of candy. Some children take 3 pieces, some
Mekhanik [1.2K]

Answer: 3 kids take 3 pieces of candy each

Step-by-step explanation:

Let the number of children that took 3 pieces is x ( total take 3*x pieces of candy)

Number of children that took 5 pieces is y ( total take 5*y pieces of candy)

1 child took 1 piece that actually means that x+y=18 and 3*x+5*y=84.

( Because total number of all kids is 19. We just deduct one kid (Let his name is John) who took only 1 candy.  So we have 19-1 =18 kids without John. The similar is with the candies. Total number is 85. We deduct 1 piece which John has taken. )

So we have 2 equations or the system of 2 equations:

1).  x+y=18

2). 3*x +5*y=84

Multuply both sides of equation 1) by 3

We have   3*x+3*y=18*3

Deduct 3*y from both sides of this equation

3*x+3*y-3*y=54-3*y

3*x=54-3*y

Substitute 3*x in equation  2).  by 54-3*y

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y=15  ( kids take 5 pieces of candy each)

Using equation 1) find x

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5 0
3 years ago
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Minimum = This is the smallest value of the data set

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Q2 = Second Quartile or Median. This is the central value so 50% of the data values lie below this point

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Maximum = This is the maximum value of the data set.

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