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3 years ago

WILL GIVE BRAINLIEST!!

Mathematics

1 answer:

Molodets [167]3 years ago

7 0

The first option is correct because it's far from the rest of the data
Second is correct too because several dots are in that area
3 and 4 are not true

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(a) A parachutist lands at a point on the line between the points A and B, and the target is an operation at A. The operation fa

mr Goodwill [35]

Answer:

a) $\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

b) $P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

Step-by-step explanation:

Part a

We assume that the parachutist lands at random point in the interval (x=A,y=B) we have a continuous random variable X. And the distribution of X would be uniform $Y\sim Unif(A,B)$ . And the density function would be given by:

$f(x) =\frac{1}{B-A} , A$

And 0 for other case.

The operation fails, if parachutist's distance to A is more than five times as much as her distance to B.

So the point P in the interval (A,B) at which the distance to A is exactly 5 times the distance to B is given by:

$P= A + \frac{5}{6} (B-A)= \frac{6A +5B -5A}{6}=\frac{A+5B}{6}$

And we can find the probability desired like this:

$P(d(P,A) \geq 5 d(P,B))= P(\frac{A+5B}{6} < X< B)$

And from the cumulative distribution function of X ficen by $F(X)\frac{X-A}{B-A}$ we got:

$\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

Part b

For this case we assume that $X\sim Gamma (2,1)$

On this case we assume that $\alpha=2, \beta= 1$

The density function for the Gamma distribution is given by:

$P(X)= \frac{\beta^{\alpha} x^{\alpha-1} e^{-\beta x}}{\gamma(\alpha)}$

And on this case we can find the probability using the complement rule like this:

$P(X>1) = 1-P(X\leq 1)=0.736$

We can solve this problem with the following excel code:

"=1-GAMMA.DIST(1;2;1;TRUE)"

And if we do it by hand we need to do this:

$P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

6 0

2 years ago

What is the nth term rule for the liner sequence below 15,7,-1,-9,-17

Volgvan

Answer:

-8n+7

Step-by-step explanation:

the difference between the values is 8, as it decreases by 8, it withh be 8n

It does not start at 8 though, so you do 15-8 to find the different which is added on which is 7 in this case

8 0

2 years ago

72 students in sixth grade at Cypress Middle school like pumkin Spice Oreos.If there are 300 Sixth grade students,what percent o

Lubov Fominskaja [6]

Answer:

19.35

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please help explanation if possible

posledela

Answer:

y =3x - 5

Step-by-step explanation:

Well one of the way to do this question is the formula given below your question, but for me, i rather do it this way

OK they gave u y=3x - 12

And they say another line is parallel, once u see the word parallel means they have the same angle, same slope, same gradient ( sorry if I give u the wrong terms, since I learn mine in Malay)

So first u got to understand the slope-intercept form

y = mx + c

y is your y coordinate

x is your x coordinate

m is your gradient ( as in how much the line slants)

c is the y - intercept, as in, if u draw a graph, the y-coordinate where your line touches the y-axis (the vertical line)

So since the say the both lines are parallel, so both of their "m" is the same that is 3. Why? Cuz just compare

y = mx + c

y = 3x - 12

Therefore the m is 3

Therefore u alredy got your first value, so put it in your slope intercept form

y = mx + c

y = 3x + c

Now how to find c? Very easy, just put in the value of y and x from the coordinate ( that the line youre finding is on) they gave u, just put the value in

They gave u

(1, - 2)

So when x = 1, y = - 2

Therefore put it in

y = 3x + c

-2 = 3 (1) + c

c = - 5

Since now u have your m and c value, your slope intercept form is done, just put it in

y = mx + c

y = 3x + (-5)

y = 3x -5

6 0

2 years ago

6. a) Rivka used the last four digits of her

bulgar [2K]

Answer: Her e-mail password is $1048222131$

Step-by-step explanation:

You know that a part of Rivka's e-mail password is formed by the last four digits of her telephone number.

The exercise gives you the last four digits of Rivka's telephone number:

$1048$

Now, in order to find the other numbers, you need to descompose $1048$ into its prime factors. Then:

$1048=2*2*2*131$

Therefore, based on this, you can determine that her e-mail password is:

$e-mail\ password=1048222131$

8 0

3 years ago