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2 years ago

Please don't troll!!!!!!!

Mathematics

1 answer:

kondaur [170]2 years ago

5 0

Answer:

Ben = $ 41

Kaden = $ 31

Step-by-step explanation:

Let initially Ben has $ p and then Kaden has $ (p - 10).

After that

Ben has= $ (p + 4)

Kaden has = $ (p- 10 + 4) = $ ( p - 6)

According to the question,

$p- 6 = \frac{7}{9}\times (p+4)\\\\9 p- 54 = 7 p + 28 \\\\2 p = 82\\\\p =41$

Initially Ben has $ 41 and Kaden has $ 31.

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Let T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear transformation, and

Klio2033 [76]

Answer:

$\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent set.

Step-by-step explanation:

Given: $\{v_1,v_2,v_3\}$ is a linearly dependent set in set of real numbers R

To show: the set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

Solution:

If $\{v_1,v_2,v_3,...,v_n\}$ is a set of linearly dependent vectors then there exists atleast one $k_i:i=1,2,3,...,n$ such that $k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0$

Consider $k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

A linear transformation T: U→V satisfies the following properties:

1. $T(u_1+u_2)=T(u_1)+T(u_2)$

2. $T(au)=aT(u)$

Here, $u,u_1,u_2$ ∈ U

As T is a linear transformation,

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\$

As $\{v_1,v_2,v_3\}$ is a linearly dependent set,

$k_1v_1+k_2v_2+k_3v_3=0$ for some $k_i\neq 0:i=1,2,3$

So, for some $k_i\neq 0:i=1,2,3$

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

Therefore, set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

6 0

3 years ago

A table of values of a linear function is shown below.

ikadub [295]

Given:

A table of values of a linear function.

To find:

The slope, y-intercept and equation of the function.

Solution:

Take any two points on the table.

Let the points are (-1, -3) and (0, -6).

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{-6-(-3)}{0-(-1)}$

$$m=\frac{-6+3}{0+1}$

$$m=\frac{-3}{1}$

m = -3

Slope of the function = -3

y-intercept of the function is the point where x = 0.

In the table y = -6 when x = 0

y-intercept = -6

Equation of a line:

y = mx + c

where m is the slope and c is the y-intercept

y = -3x + (-6)

y = -3x - 6

Equation of a function is y = -3x - 6.

3 0

3 years ago

A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form

Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity $v_o$ of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

$h = -16t^2 +v_ot + 8$

Thus;

Replacing the value of $v_o$ = 1120 and h = 0 (i.e. when h =0) in the above expression; we have:

$0= -16t^2 +(1120)t + 8$

$= -16t^2 +(1120)t + (8-0)$

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² - 140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula $\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ , we have:

$= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}$

$= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}$

$= \dfrac{140 \pm \sqrt{19608}}{4}$

$= \dfrac{140 \pm 140}{4}$

$=\dfrac{140+ 140}{4} \ \ \ OR \ \ \ \dfrac{140-140}{4}$

$=\dfrac{280}{4} \ \ \ OR \ \ \ 0$

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

6 0

3 years ago

Please answer this correctly

alexgriva [62]

Answer:

50% off :)

Step-by-step explanation:

use the purple coupon to take off half of the whole price so you spend less overall. And the only requirement is that it needs to be over the price of 350 (originally) , so your item is eligible.

6 0

3 years ago

Read 2 more answers

5000000000000000+ 100

Tasya [4]

Answer:

5000000000000100

Step-by-step explanation:

the question explains itself just ad 100

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3 years ago