Question

What is the equation linethatis perpendicular to the given line and passes through the point (3,0)?​

Answer 1

Answer:

3y+x = 3

Step-by-step explanation:

for the point ( 3,0)

x=3 , y= 0

the equation for the line is given as

y-y1= m(x-x1)

for perpendicular ,

m= -1/x

so

y-0 = -1/3(x-3)

3y= -x +3

3y+x=3