What is the equation linethatis perpendicular to the given line and passes through the point (3,0)?
1 answer:
Answer:
3y+x = 3
Step-by-step explanation:
for the point ( 3,0)
x=3 , y= 0
the equation for the line is given as
y-y1= m(x-x1)
for perpendicular ,
m= -1/x
so
y-0 = -1/3(x-3)
3y= -x +3
3y+x=3
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