Answer:
$356.00
Step-by-step explanation:
If d represents the discounted price, and p is the original price, you have ...
d = p - 20% × p = p(1 -20%) = 0.80p
Then the original price is ...
p = d/0.80 . . . . . divide by the coefficient of p
p = $284.80/0.80 = $356.00
The price before the discount was $356.00.
Answer:
Walkway is 3 feet wide.
Step-by-step explanation:
Given:
Length of the building is 150 ft
width of the building is 100 ft
walkway is x ft wide.
Total area(around and including the building) = 16536 square feet
Solution:
Length of the total area will be = length of the building + width of walkway from 2 sides = 
Width of the total area will be = width of the building + width of walkway from 2 sides = 
Now Total area(around and including the building) = Length of the total area
Width of the total area
Now solving for both equation we get.
Now, We get 2 values for x which -128 and 3 but the width of the building can't be in negative value hence we will consider value of x be 3.
∴ Width of the walkway is 3 ft.
Answer:
See answer and graph below
Step-by-step explanation:
∬Ry2x2+y2dA
=∫Ry.2x.2+y.2dA
=A(2y+4Ryx)+c
=∫Ry.2x.2+y.2dA
Integral of a constant ∫pdx=px
=(2x+2.2Ryx)A
=A(2y+4Ryx)
=A(2y+4Ryx)+c
The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2
Answer:
5
Step-by-step explanation:
The 32 that have blue and green ribbons include the 16 that have all three, so there are only 32 -16 = 16 that have only blue and green ribbons.
The 31 that have green and white ribbons likewise include the 16 with all three, so there are only 31 -16 = 15 that have only green and white ribbons.
The 38 that have blue and white ribbons include the 16 with all three, so there are only 38 -16 = 22 that have only green and white ribbons.
__
If we add the numbers of blue, green, and white ribbons, we are counting twice the numbers that have 2 ribbons, and 3 times the numbers that have 3 ribbons. We want to count each kind of ribbon-holder only once. Hence the number of individual dogs with any number of ribbons is only ...
62 +55 +63 -(16 +15 +22) -2(16) = 95
Of the 100 dogs, 95 have ribbons, so 5 dogs have not learned any tricks.
