Answer:
Distance LM = 5.20 unit (Approx.)
Step-by-step explanation:
Given coordinates;
L(1, 4, 7) and M(2, 9, 8)
Find:
Distance LM
Computation:
Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²
Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²
Distance LM = √(1)² + (5)² + (1)²
Distance LM = √1 + 25 + 1
Distance LM = √27
Distance LM = 3√3 unit
Distance LM = 3(1.732)
Distance LM = 5.196
Distance LM = 5.20 unit (Approx.)
Answer:
Step-by-step explanation:
The solution of the problem has been solved on paper and attached in the attachment section. Kindly refer to that and feel free to ask any doubt.
Use the substitution method
V= s^3
2*2*2= 8 cm^ 3
Answer : 8 cm^ 3 - A
Dimensions of rectangle = 12 + x and 14 + x
(12 + x) (14 + x) = 288
x^2 + 26x + 168 = 288
x^2 + 26x - 120 = 0
(x + 30) (x - 4) = 0
x=-30, x =4
since 4 is positive
the dimensions increased by 4 feet
check the answer
12+4 = 16
14 +4 = 18
18*16 =288