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3 years ago

A bike at rest moves to 2 m/s in 2 seconds.

Physics

2 answers:

Sergio039 [100]3 years ago

3 0

Answer:

Explanation:

When at rest, initial velocity = 0

In 2 seconds, final velocity = 2 m/s

Acceleration = (final velocity - initial velocity) / time

= (2 - 0) / 2

= 1 m/s^2

Anastaziya [24]3 years ago

3 0

Answer:

1m/s^2

Explanation:

Acceleration = (final velocity - initial velocity) / time = (2-0)/2 = 1m/s^2

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lana66690 [7]

Answer:

C. 720 N up

Explanation:

Newton's third law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A"

In this situation, we can imagine the man to be object A and the bench as object B. The force exerted by the man on the bench is:

720 N, down

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3 years ago

What factors determine electric potential?

NNADVOKAT [17]

Answer: C. Charge and distance

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3 years ago

In machines and engines,A. there will be no friction.B. friction increases fuel efficiency.C. the process of overcoming friction

il63 [147K]

Think of a car, when we have to add oil. If we didn't then the friction would cause so much heat that the engine would break and fall apart.

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4 years ago

You are designing a 108 cm3 right circular cylindrical can whose manufacture will take waste into account. There is no waste in

FinnZ [79.3K]

Explanation:

It is given that,

The volume of a right circular cylindrical, $V=108\ cm^3$

We know that the volume of the cylinder is given by :

$V=\pi r^2 h$

$108=\pi r^2 h$

$h=\dfrac{108}{\pi r^2}$ ............(1)

The upper area is given by :

$A=32r^2+2\pi rh$

$A=32r^2+2\pi r\times \dfrac{108}{\pi r^2}$

$A=32r^2+\dfrac{216}{r}$

For maximum area, differentiate above equation wrt r such that, we get :

$\dfrac{dA}{dr}=64r-\dfrac{216}{r^2}$

$64r-\dfrac{216}{r^2}=0$

$r^3=\dfrac{216}{64}$

r = 1.83 m

Dividing equation (1) with r such that,

$\dfrac{h}{r}=\dfrac{108}{\pi r}$

$\dfrac{h}{r}=\dfrac{108}{\pi 1.83}$

$\dfrac{h}{r}=59 \pi$

Hence, this is the required solution.

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3 years ago

The maximum acceleration a pilot can stand without blacking out is about 7.0 g. In an endurance test for a jet plane's pilot, wh

steposvetlana [31]

Answer:

$v=54.00m/s$

Explanation:

7.0g is $7\times$ the acceleration due to gravity.

Given that $g=7\times9.8m/s^2$ , acceleration can be calculated as:

$a=7\times9.8m/s^2\\a=68.6m/s^2$

Since circular motion is involved and our radius of curvature is given as, $r=\frac{85}{2}m$ , <em>centripetal acceleration </em>is given by the formula: $a=v^2/r$ .

Make $v^2$ subject of the formula to find $v$ :

$a=v^2/r\\v^2=ar=68.6\times(85/2)\\v^2=2915.5\\v=\sqrt{2915.5}\\v=54.00m/s$

The maximum speed of the pilot is $54m/s$

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4 years ago