Answer:
10
Step-by-step explanation:
braniyest pls
Answer:
272.17 ft
Step-by-step explanation:
Since the angle of depression of the sighting equals the angle of elevation of the lighthouse from the boat, using trigonometric ratios,
tanθ = x/d where θ = angle of sighting, x = height of lighthouse =55 ft and d = distance of boat from lighthouse at sighting
So, d = x/tanθ
when θ = 8.1°, for the first sighting,
d₁ = 55/tan8.1 = 386.45 ft
when θ = 25.7°, for the second sighting,
d₂ = 55/tan8.1 = 114.28 ft
The distance the boat traveled between the two sightings is thus d₁ - d₂ = 386.45 ft - 114.28 ft = 272.17 ft
To solve this problem you must apply the proccedure shown below:
1. You have the following parametric equations given in the problem above:
<span> x=e^3t
y=e^-t</span>
2. Therefore, you must solve fot et in the second equation, as below:
y=e^-t
y=1/e^t
e^t=1/y
3.Substitute into the first equation:
x=e^3t
x=(e^t)^3
x=(1/y)^3
x=1/y^3 (y>0)
The answer is: x=1/y^3 (y>0)
Answer:
Normal speed = 711.11 km/h (Approx)
Step-by-step explanation:
Assume;
Normal speed = x
New speed = x - 25% of x = 0.75 x
Time taken = t
New time taken = t + 1.5 hour
Total distance
Computation:
Total distance = 3,200 km
Speed = Distance/Time
x = 3200 / t
t = 3200/x
so,
0.75 x = 3200 / (t+1.5)
0.75 x = 3200 / (3200/x+1.5)
0.75 x = 3200 / [(3200 + 1,5x)x]
x = 711.11 km/h
Normal speed = 711.11 km/h (Approx)
Answer:
I believe it's 20
Step-by-step explanation:
I'm sorry if it's wrong, but I'm pretty sure it's correct