Atomic emission spectra are like fingerprints for the elements, because it can show the number of orbits in that elements as well as the energy levels of that element. As each emission of atomic spectra is unique, it is the fingerprint of element.
<u>Explanation:
</u>
Each element has unique arrangement of electrons in different energy levels or orbits. So depending upon the difference in energy of the orbital, the emission spectra will be varying for each element. As the binding energy and excitation energy is not common for any two elements, so the spectra obtained when those excited electrons will release energy to ground state will also be unique.
As in atomic emission spectra, the incident light will be absorbed by the electrons of those elements making the electron to excite, then the excited electron will return to ground state on emission of radiation of energy. Thus, this energy of emission is equal to the difference between the energy of initial and final orbital. So the spectra will act like fingerprints for elements.
Length of the sheet is given as
width of the sheet is given as
now let say its thickness is "t"
so the volume of the sheet is given as
mass of the sheet is given as
now we have
by solving above we have
so the thickness of sheet will be above
You can only add or subtract numbers in scientific notation if they have
the same power of 10. If they're different, then you have to change one
to match the other one.
Here are both ways to do your example:
3.72x 10^9 = 37.2x10^8
(37.2 x 10^8)+(5.46 x 10^8) = (37.2+5.46) x 10^8 = 42.66x10^8 = <em>4.266x10^9</em>
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5.46 x 10^8 = 0.546 x 10^9
3.72 x 10^9 + 0.546 x 10^9 = (3.72 + 0.546) x 10^9 = <em>4.266 x 10^9</em>
Multiply 5 newton by each height. 1st is 5 joules, 2nd is 7.5, while 3rd is 10 joules.
Answer:
The answer is given below
Explanation:
Things provided in the statement:
Pressure <em>P1</em> = 120 kPa and <em>P2</em> = 5.6 MP or 5600 kPa
Power, <em>W</em> = 7 kW
Elevation difference = ∆z = 10 m
Mass of flow = m˙
So potential energy changes may be significant
Specific volume of water V= 0.001 m³/kg
Now putting the values in the formula
Power, <em>W </em>= m˙ x V (<em>P1 - P2</em>) + m˙ x g x ∆z
7 = m˙ x 0.001 (5600 - 120 ) + m˙ x 9.8 x 10 x (1 kJ/kg/ 1000 m^2/s^2)
7 = m˙ x 5.48 + m˙ x 0.098
7 = m ˙x 5.38
m˙ = 7/5.38
So mass flow m˙ = 1.301 kJ/s
